Question

a motorboat starts from rest and moves with uniform acceleration . if it attains the velocity of 15 m /s in 5 s, calculate the acceleration and the distance travelled in that time

Answer 1

Hii...
Here is your answer...

Solution:-
Initial velocity=0
Final velocity=15m/s
Time =5seconds

So,
$acceleration = \frac{v - u}{t} \\ = > \frac{15 - 0}{5} \\ = > \frac{15}{5} \\ = > 3$
Acceleration=3m/s^2

Now,
we have to find Distance travelled,we will find it by using following equation:-
$= > s = ut + \frac{1}{2} a {t}^{2} \\ = > s = 0 \times 5 + \frac{1}{2} \times 3 \times5 \times 5 \\ = > s = 0 + \frac{1}{2} \times 75$
$= > s = 37.5$

Hence,
Distance travelled=37.5m

Hope it helps uh...✌️✌️✌️

Answer 2

Here's the answer

Given =>

Initial velocity = 0 m/s

Final velocity = 15 m/s

Time taken = 5 second


To find =>

Acceleration = ?

Distance travelled = ?

We know that,

${\boxed {\boxed { \boxed { \sf{Acceleration = \frac{v - u}{t}} }}}}$

$\sf{= \frac{15 - 0}{5}}$

$\sf {= 3 \: m/s {}^{2}}$

Now,

By using second kinematical equation,

$\sf{s = ut + \frac{1}{2}at {}^{2}}$

$\sf{s = 0 + \frac{1}{2} \times 3 \times 25}$

$\sf{= \frac{75}{2}}$

$\sf{ = 37.5 \: m}$

Distance covered = 37.5 metre