A motorboat takes 6 hour to cover 100km upstream and 30 km downstream.if the motorboat goes 75km downstream and returns back to its starting point in 8 hours.find the speed of the boet in still water and the speed of stream.
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Let the downstream speed = x+y=a
upstream speed = x-y=b
According to the question
100/x+y + 30/x-y = 6
75/x+y +75/x-y =8
100a+30b=6 (1)
75a+75b=8(2)
divide (1) by 2 we get
50a+15b=3 ( 3)
equating(2) and (3) we get
50a+15b = 3 (3)x5
75a+75b=8
250a+75b=15
75a+75b=8
175a=7
a=1/25 implies x+y=25 (4)
substituiting a=50 in equation(3) we get
15b=1 implies b=1/15 implies x-y=15 (5)
equating (4) and (5) we get
x+y=25
x-y=15
therefore x=20km/hr i.e. speed of motorboat in still water is 20km/hr
y=5km/hr i.e. speed of the stream is 5km/hr
imstranger1234:
plz can u solve it on a paper??
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