A motorboat whose speed in still water is 18km/h, takes 1hr more to go 24km upstream thqn to return to the same spot. Find the speed of the stream. This question is from Quadratic equation. plzz its urgent .. I will mark brainlist
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Hi..
Here the ans is...
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@shuzu
Here the ans is...
Hope it helps u dear. ☺
Mark as brainliest if I deserve. ❤
@shuzu
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shuzu:
wlcm frnd..^-^
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hey friend!!!!
here is your answer
Let the speed of the stream be x km/hr
Speed of the boat in still water = 18 km/hr
Speed of the boat in upstream = (18 - x) km/hr
Speed of the boat in downstram = (18 + x) km/hr
Distance between the places is 24 km.
Time to travel in upstream = d / (18 - x) hr
Time to travel in downstream = d / (18 + x) hr
Difference between timings = 1 hr
[24 / (18 - x)] - [24 / (18 + x)] = 1
⇒ 24 [1 / (18 - x)] - [1 / (18 + x)] = 1
⇒ [1 / (18 - x)] - [1 / (18 + x)] = 1/24
⇒ (18 + x - 18 + x) / (324 - x2) = 1/24
⇒ (2x) / (324 - x2) = 1/24
⇒ 324 - x2 = 48x
⇒ x2 - 48x + 324 = 0
⇒ (x + 54)(x - 6) = 0
x = - 54 or 6
Speed of the stream can not be negative.
Therefore, speed of the stream is 6 km/hr.
hope it will help you
here is your answer
Let the speed of the stream be x km/hr
Speed of the boat in still water = 18 km/hr
Speed of the boat in upstream = (18 - x) km/hr
Speed of the boat in downstram = (18 + x) km/hr
Distance between the places is 24 km.
Time to travel in upstream = d / (18 - x) hr
Time to travel in downstream = d / (18 + x) hr
Difference between timings = 1 hr
[24 / (18 - x)] - [24 / (18 + x)] = 1
⇒ 24 [1 / (18 - x)] - [1 / (18 + x)] = 1
⇒ [1 / (18 - x)] - [1 / (18 + x)] = 1/24
⇒ (18 + x - 18 + x) / (324 - x2) = 1/24
⇒ (2x) / (324 - x2) = 1/24
⇒ 324 - x2 = 48x
⇒ x2 - 48x + 324 = 0
⇒ (x + 54)(x - 6) = 0
x = - 54 or 6
Speed of the stream can not be negative.
Therefore, speed of the stream is 6 km/hr.
hope it will help you
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