A motorcar is moving with a velocity of 108km/h and it takes 4 seconds to stop after the application of brakes. Calculate the force exerted on the car if its mass is 1800kg
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force exerted on the car if its mass is 1800kg is 13500 N
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Initial velocity = 108 km/h = 30 m/s
Final velocity = 0 m/s (rest)
Time taken = 4 s
Mass = 1800 kg
We know, F(net) = ma
⇒ F = m(∆v)/t = m(v - u)/t = - mu/t
⇒ F = (1800 kg)(- 30 m/s)/(4 s)
⇒ F = - 13500 N or - 13.5 kN
∴ Force exerted by the car is of 13.5 kN in the opposite direction of the motion of it.
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