Question

A motorcar of mass 1,200 kg is moving along a straight line with a uniform velocity of 90 km/h. Its velocity is slowed down to 18 km/h in 4 s by an unbalanced external force. Calculate the acceleration and change in momentum. Also calculate the magnitude of the force required.​

Answer 1

$\huge\mathfrak{Bonjour!!}$

$\huge\bold\purple{Answer:-}$

⏩ Here, m= 1,200 kg

Initial velocity, u= 90 km/h = 90 × 5/18 m s^-1 = 25 m s^-1

Final velocity, v = 18 km/h = 18 × 5/18 m s^-1 = 5 m s^-1

Time , t= 4s

Now, we know that,

Acceleration, a= v-u/t

= 5 - 25/4 = -5 m/s²

→Therefore, magnitude of acceleration = 5 ms^-2. Ans.

Now, change in momentum = m(v-u)

= 1,200 ( 5 - 25)

= -24,000 kg m s^-1

Therefore,

→ Magnitude of change in momentum = 24,000 kg m/s. Ans.

→ Magnitude of force= Change in momentum/ Time taken

= 24,000/4

= 6,000 N. Ans.

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Answer 2

Answer:

$\huge\underline\mathfrak\purple{Solution}$