Question

A motorcycle accelerate uniformly form 10m / to 20m/s .calclate (I) acceleration and ( II) the distance covered.

Answer 1

★ Correct Question ★

A motorcycle accelerates uniformly from 10 m/s to 20 m/s in 12.0 s. Calculate (1) acceleration and (2) the distance covered.

Given:

• Initial speed (u) = 10 m/s
• Final speed (v) = 20 m/s
• Time (t) = 12 seconds

To Calculate:

• (1) Acceleration (a) = ?
• (2) Distance (S) = ?

Formula to be used:

$(1) \: \: a = \frac{v - u}{t} \\ \\ (2) \: \: S = ut \: + \frac{1}{2} at ^{2}$

To find "a" :

$a \: = \frac{v - u}{t} = \frac{20 - 10}{12} \\ \\ \implies a = \frac{10}{12 } \: = \frac{5}{6} m/s ^{2}$

To calculate "S" :

$S \: = ut + \frac{1}{2} at ^{2} \\ \\ \implies \: (10 \times 12) + \frac{1}{2} \times ( \frac{5}{6} ) \times ( {12})^{2} \\ \\ \implies \: 120 + \frac{1}{2} \times \frac{5}{6} \times 144 \\ \\ \implies \: 120 + (5 \times 12) \\ \\ \implies \: 120 + 60 \\ \\ \implies \: 180 \: m \:$