Physics, asked by pukhraj20, 11 months ago

A motorcycle and a car start from rest from the same place at the same time and travel in the same direction.
The motorcycle accelerates at 1.0 m/s^2 up to a speed of 36 km/h and the car at 0.5 m/s^2 up to a speed of 54 km/h .The time at which the car would overtake
the motorcycle is​

Answers

Answered by vibusanjr0810
5

Answer:

car will overtake bike after 35  sec

Explanation:

The distance from starting point, where bike reaches it final speed 10 m/s is given by  

 

v2 = 2×a×S ; hence S = v2/(2a) = 100/2 = 50 m

 

Time t1 for the bike to reach final velocity = v/a = 10/1 = 10 s.  

 

The distance from starting point, where car reaches it final speed 15m/s is given by  

 

v2 = 2×a×S ; hence S = v2/(2a) = 225/(2×0.5) = 225 m ................................(1)

 

Time t2 for the car to reach final velocity = v/a = 15/0.5 = 30 s.

 

In this 30 s duration of car travel, distance travelled by bike = Initial 50 m in 10 s + distance travelled in 20 s with uniform speed 10 m/s

 

= 50 + 20×100 = 250 m ............................(2)

 

From (1) and (2), we know that after 30 s the distance between car and bike = 25 m.

 

After 30 s , both bike and car are moving with uniform speed. Car speed is 15 m/s and bike speed is 10 m/s.

hence additional time to cover this 25 m gap = 25/(15-10) = 5 s.

 

total time is 30+5 = 35 s.

 

Car will overtake bike after 35 s

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