Question

A motorcycle at rest uniform velocity of 72kmph in 20secend find the value of acceleration of motorcycle

Answer 1

Correct question:

A motorcycle is at rest, then after 20sec velocity is 72km/hr motion is uniform. Find the acceleration of the motorcycle .

Given :

Initial velocity of motorcycle,u ( at rest ) = 0

final velocity of motorcycle, v = 72km/hr = 20 m/s

And t = 20 sec

To find :

Acceleration of the motorcycle

${\blue{\boxed{\large{\bold{Formula's}}}}}$

Kinematic equations for uniformly accelerated motion.

$\bf\:v=u+at$ $\bf\:s=ut+\frac{1}{2}at{}^{2}$

$\bf\:v{}^{2}=u{}^{2}+2as$

and

$\bf\:s_{nth}=u+\frac{a}{2}(2n-1)$

Solution :

We have to find the acceleration of the motorcycle.

By using the equation of motion

$\sf\:v=u+at$

Now put the given values

$\sf\:20=0+a\times20$

$\sf\:a=\dfrac{20}{20}$

$\sf\:a=1ms^{-2}$

Hence, Acceleration of the motorcycle is 1m/s²

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More Information:

Acceleration is the change of velocity

So if velocity is 0

It means there is no acceleration