a motorcycle can accelerate from the rest to 28 m/s in only 4s what is its acceleration
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Hope this helps you
Explanation:
Starting velocity u =0 m/s
End velocity v= 28m/s in time t= 4sec
If accleration = f
v= u+ft , 28= 0+ f × 4 , f = 28/4 = 7 m/s^2
Accleration = 7m/sec^2
If distance travelled =S
S= ut +1/2 ft^2 = 0 × 4+(1/2)7× 4^2 =56 m
Distance travelled in 4 sec = 56 m
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