A motorcycle has a constant Acceleration of 2.5 m/s² both the velocity and the acceleration of the motorcycle point in the same direction. How much time is required for a motorcycle to change its speed from. a) 16 to 31 m/s
b) 51 to 66 m/s
Answers
Answered by
8
acceleration= 2.5m/s^2
a) Initial velocity (u)= 16 m/s
Final Velocity(v)= 31 m/s
Now,
v=u+at
=> 31 = 16+2.5*T
=>31-16/2.5= T
=>6 sec= Time
So, The time required is 6 Sec
b) Initial Velocity (u)= 51 m/s
Final Velocity (v)= 66m/s
Now,
v= u+at
=> 66= 51+2.5*t
=> 66-51/2.5= t
=> time = 6 sec
So, The time required is 6 sec.
a) Initial velocity (u)= 16 m/s
Final Velocity(v)= 31 m/s
Now,
v=u+at
=> 31 = 16+2.5*T
=>31-16/2.5= T
=>6 sec= Time
So, The time required is 6 Sec
b) Initial Velocity (u)= 51 m/s
Final Velocity (v)= 66m/s
Now,
v= u+at
=> 66= 51+2.5*t
=> 66-51/2.5= t
=> time = 6 sec
So, The time required is 6 sec.
Similar questions