A motorcycle is being driven at a speed of 20m/s when breaks are applied to bring it to rest in five seconds. The deceleration produced in this case will be:
a) +4m/s²
b) -4m/s²
c) +0.25m/s²
d) -0.25m/s²
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simple is v=u-at . v is final velocity and u is initial velocity. a is acceleration and t is the time. 0=20+5a.
a=-4m/s2.
a=-4m/s2.
prathamesh87654321:
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