Physics, asked by prathamesh87654321, 11 months ago

A motorcycle is being driven at a speed of 20m/s when breaks are applied to bring it to rest in five seconds. The deceleration produced in this case will be:
a) +4m/s²
b) -4m/s²
c) +0.25m/s²
d) -0.25m/s²

Answers

Answered by praneethks

simple is v=u-at . v is final velocity and u is initial velocity. a is acceleration and t is the time. 0=20+5a.
a=-4m/s2.

prathamesh87654321: U r making fool of me

prathamesh87654321: 0=20-5a how?

praneethks: hello finally it comes to rest so final velocity is zero initially it is 20 m/s2. do you know that acceleration is change in velocity/ time taken apply it . you

praneethks: will understand final velocity- initial velocity/ time taken is formula for acceleration okay i am better qualified than you okay .

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A motorcycle is being driven at a speed of 20m/s when breaks are applied to bring it to rest in five seconds. The deceleration produced in this case will be: a) +4m/s² b) -4m/s² c) +0.25m/s² d) -0.25m/s²

Answers

A motorcycle is being driven at a speed of 20m/s when breaks are applied to bring it to rest in five seconds. The deceleration produced in this case will be:
a) +4m/s²
b) -4m/s²
c) +0.25m/s²
d) -0.25m/s²