a motorcycle is moving with a velocity of 90km/h and it takes 5s to stop after applied brake calculate force exerted by the brakes on the motorcycle if it's mass along with the rider is 200kg
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Answered by
6
90km/h=90*1000/60*60=25m/s
using first equation of motion
v=u+at
0=25+a*5
a=-5m/s^2
so
f=mass×acceleration
F=200×5=1000N
pls mark brainleist
using first equation of motion
v=u+at
0=25+a*5
a=-5m/s^2
so
f=mass×acceleration
F=200×5=1000N
pls mark brainleist
hidivyanshp4f9il:
yup but we know its retarding force which direction does negative sign indicate if we are using vector form we should write icap j cap or k cap
Answered by
11
Hello,
Time taken to stop = 5 seconds
Initial velocity = 90 km/hr = 25 m/sec
Final velocity = 0 m/sec ( since, body stopped after 5 seconds)
So,
Acceleration =final velocity - initial velocity ÷time taken
So,
Acceleration = 0-25/5 = (- 5)m/sec²
Now, acceleration in negative means retardation.
Now
From newton's second law of motion
Force = mass *acceleration
Force = 200 *( - 5) = (-1000)N
Force in negative means that the force is applied in opposite direction of motion.
Hope this will be helping you
WARM REGARDS
Sahil khirwal
Time taken to stop = 5 seconds
Initial velocity = 90 km/hr = 25 m/sec
Final velocity = 0 m/sec ( since, body stopped after 5 seconds)
So,
Acceleration =final velocity - initial velocity ÷time taken
So,
Acceleration = 0-25/5 = (- 5)m/sec²
Now, acceleration in negative means retardation.
Now
From newton's second law of motion
Force = mass *acceleration
Force = 200 *( - 5) = (-1000)N
Force in negative means that the force is applied in opposite direction of motion.
Hope this will be helping you
WARM REGARDS
Sahil khirwal
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