A motorcycle is moving with a velocity of 90km per hour and it takes 5 seconds to stop after the breaks are applied. Calculate the force exerted by the breaks on the motorcycle of its mass along with the rider.
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Initial velocity, u = 90 km/h or 25 m/s.
Final velocity, v = 0 bcoz it stops
Mass = 200 kg
Now, force exerted by the brakes will be the acceleration they produce to stop the motorcycle.
Therefore we will use the formula, v = u+at
v= u+ at
0= 25 + a * 5
-25= a* 5
Therefore, force exerted by the brakes is -1000 N to stop the motorcycle.
-5= a
Now, force exerted = product of mass and acceleration
= 200* -5
= -1000 N
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