Question

a motorcycle is travelling at 30m/s on a circular road of radius 300 m its speed is increasing at the rate of 4 m/ s square. calculate the acceleration of the car​

Answer 1

a=v^2/r

a=30^2/300

a=3

Answer 2

The acceleration of the car is $5\ m/s^2$.

Explanation:

It is given that,

Speed of the motorcycle, v = 30 m/s

Radius of the circular path, r = 300 m

The tangential acceleration acting in the motorcycle is, $a_t=4\ m/s^2$

The net acceleration on the motorcycle is given by :

$a=\sqrt{a_t^2+a_c^2}$

$a_c=\dfrac{v^2}{r}$ (centripetal acceleration)              

$a_c=\dfrac{30^2}{300}=3\ m/s^2$

So,

$a=\sqrt{4^2+3^2}$

$a=5\ m/s^2$

So, the acceleration of the car is $5\ m/s^2$. Hence, this is the required solution.

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