A motorcycle moving with a speed of 10m/s per second is stopped by applying brakes which produce a uniform acceleration of - 0.5m/s2 per second square calculate the distance before it stops
Answers
Answered by
2
given,
initial velocity, u=10m/s
final velocity,v=0
acceleration, a= -0.5m/s²
distance,s= ?
with the following formula v²-u²= 2as
=0²-10²=2x(-0.5)x S
=> -100= -1S
=>1S =100
=>S= 100 m
hence the distance is 100 m hope it helps you..
initial velocity, u=10m/s
final velocity,v=0
acceleration, a= -0.5m/s²
distance,s= ?
with the following formula v²-u²= 2as
=0²-10²=2x(-0.5)x S
=> -100= -1S
=>1S =100
=>S= 100 m
hence the distance is 100 m hope it helps you..
Kino1:
Kino
which class do you read
mark my answer brainliest buddy
class 9
oh nice
I am also in 9th
that's nice
ok bye
once again thanks for your answer
no problem
Answered by
1
Here's the answer hope it helps you
Attachments:
Similar questions