Question

a motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s ^2 . calculate the speed of the motorcycle after 10 secoands and distance travelled in time

please tell me with explanation​

Answer 1

Answer:

Here , u = 5 m/s , a = 0.2 m/s2  , t = 10 s , s = ? , v = ?

From , v  = u +  at

v = 5 + 0.2 × 10  

= 7 m/s

From, v2  = u2 + 2aS

72 =  52  + 2 × 0.2 × S  

49 = 25 + 0.4S  

49 - 25 = 0.4S

0.4S = 24  

S = 24 / 0.4  

S = 60 m

Answer 2

Explanation:

v=u+ at

v=5+0.2*10

v=7 m/s

from v2=u2+2as

=71=52+2*0.2*5

49=25+0.45

0.4s=24

s=24/0.4

s=60m