Question

A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled in this time.​

Answer 1

Answer:Answer

u=5m/sv=?a=0.2m/s  

2

t=10sec

v=u+at

v=5+0.2×10

v=7m/s

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Now distance traveled,

s=?

v  

2

=u  

2

+2as

7  

2

=5  

2

+2×0.2×s

49=25+0.4s

49−25=0.4s

s=  

0.4

24

​

 

s=60m

​

 

Answer 2

Answer:

v = u + at

v = 5 + 0.2×10

v = 5 + 20

v = 25 m/s