Question

A motorcycle moving with a speed of 5 m/s obtains an acceleration of 0.2 m/s².
Calculate the speed of the motorcycle after 10 seconds.

Answer 1

Provided that:

• Initial velocity = 5 mps
• Acceleration = 0.2 mps sq.
• Time = 10 seconds

To calculate:

• Final velocity

Solution:

• Final velocity = 7 mps

Using concept:

• First equation of motion

Using formula:

• v = u + at

Where, a denotes acceleration, u denotes initial velocity, v denotes final velocity and t denotes time taken.

Required solution:

»»» v = u + at

»»» v = 5 + 0.2(10)

»»» v = 5 + 2

»»» v = 7 mps

»»» Final velocity = 7 mps

Know more:

$\begin{gathered}\boxed{\begin{array}{c}\\ {\pmb{\sf{Three \: equation \: of \: motion}}} \\ \\ \sf \star \: v \: = u \: + at \\ \\ \sf \star \: s \: = ut + \: \dfrac{1}{2} \: at^2 \\ \\ \sf \star \: v^2 - u^2 \: = 2as\end{array}}\end{gathered}$

Answer 2

• Initial velocity=u=5m/s
• Acceleration=a=0.2m/s^2
• Time=10s=t.
• Final velocity=v=?

Using first equation of kinematics

$\boxed{\sf v=u+at}$

$\\ \sf\longmapsto v=5+0.2(10)$

$\\ \sf\longmapsto v=5+2$

$\\ \sf\longmapsto v=7m/s$