A motorcycle moving with a speed of 5 meter/second is subjected to an acceleration of 0.2 meter/second square . Calculate the speed of motorcycle after 10 seconds
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Initial velocity (u) =5m/s
Acceleration (a) =0.2m/s^2
Time(t) = 10s
Using second equation of motion
ut +(1/2)at^2
= ( 5)(10) +(1/2)(0.2)(10)^2
= 50 + 10
= 60m
So, the distance covered by that body is 60m.
Acceleration (a) =0.2m/s^2
Time(t) = 10s
Using second equation of motion
ut +(1/2)at^2
= ( 5)(10) +(1/2)(0.2)(10)^2
= 50 + 10
= 60m
So, the distance covered by that body is 60m.
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