Question

a motorcycle moving with a speed of 5 metre per second is subjected to an acceleration of 0.2 metre per second square0. calculate the speed of motorcycle after 10 seconds and the distance travelled in this time​

Answer 1

Answer:

a) the speed after 10s is 7m/s

b) the distance travelled in 10s is 60m

Explanation:

a) u= 5m/s

a=

$0.2 \frac{m}{s}^{2}$

t= 10s

Using 2nd Equation of Motion

v=u+at

v=5+(0.2)(10)

v=5+2

v=7

After 10 seconds, speed will be 7m/s

b)

Using 3rd equation of motion

S (Distance) =

$\frac{1}{2} at ^{2}$

S=

$(5)(10) + \frac{1}{2} (0.2)( {10}^{2} )$

S=

$50 + \frac{1}{2} \times 20$

(2 cancels out 20)

50 + 10 = 60

Hence distance travelled in 10 s is 60m