a motorcycle moving with a speed of 5 metre per second is subjected to an acceleration of 0.2 metre per second square. calculate the speed of the motor cycle after 10 seconds and the distance travelled in this time
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hiiiiiiii
u = 5 m/seca = 0.2 m/sec ^ 2t = 10 sec
USING 1ST EQ OF MOTION,
v = u + atv = 5 + 0.2×10v
= 5 + 2v = 7 m/sec
FINAL VELOCITY = 7 m/sec
2nd EQ OF MOTION,
s = ut + 1/2 at^2s
= 5 × 10 + 1/2 × 2/10×10×10s = 50 + 10s = 60m
DISTANCE = 60 m
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u = 5 m/seca = 0.2 m/sec ^ 2t = 10 sec
USING 1ST EQ OF MOTION,
v = u + atv = 5 + 0.2×10v
= 5 + 2v = 7 m/sec
FINAL VELOCITY = 7 m/sec
2nd EQ OF MOTION,
s = ut + 1/2 at^2s
= 5 × 10 + 1/2 × 2/10×10×10s = 50 + 10s = 60m
DISTANCE = 60 m
HOPE IT HELPS :):):):):):):)MARK AS BRAINLIEST
kaustov2:
Thanks bro
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