a motorcycle moving with a speed of 5 metre per second is subjecyed on to an acceleration of 0.2 metre per second sq. calculate the the speed of the motorcycle after 10 seconds and the distance covered by it in this time
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HEY!!
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▶Initial speed, u = 5m/s
▶Acceleration, a = 0.2m/s2
▶Time taken, t = 10s
✴Using equation of motion,
v = u + at
= 7 m/s
✴For distance, you use either either of the equation of motion
✔s = ut + at2/2 0r v2 - u2 = 2as
✔s = [v2 - u2]/2a = 60m
hope it helps!!
__________________________________
▶Initial speed, u = 5m/s
▶Acceleration, a = 0.2m/s2
▶Time taken, t = 10s
✴Using equation of motion,
v = u + at
= 7 m/s
✴For distance, you use either either of the equation of motion
✔s = ut + at2/2 0r v2 - u2 = 2as
✔s = [v2 - u2]/2a = 60m
hope it helps!!
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