Question

A motorcycle moving with a speed of 5 metre per second is subjected to an acceleration of 0.2 metre per second square calculate the speed of the motor cycle after 10 seconds and the distance travelled in this time​

Answer 1

The Solution for this is very Easy.

You have to just know, the Acceleration formula -

a = v - u / t ; where a = acceleration, v = final velocity, u = initial velocity, t = time taken

and The equations of motions, which you can find in your Physics book or the internet. Of those, I used this to find the answer -

S = (u + v) t / 2 ; where S = displacement / distance

Solution:

initial Speed = 5 m/s (u)

acceleration = 0.2 m/s^2 (a)

time taken = 10 secs (t)

final speed = ? (v) (to find)

a = v - u / t [acceleration formula]

putting values and taking v as x since unknown,

0.2 = x - 5 / 10

or, 0.2 × 10 = x - 5

or, 2 + 5 = x

or, x = 7

Answer 1 : The speed of the motorcycle after 10 seconds is 7 m/s.

Displacement = ? (S) (to find)

final velocity = 7 m/s (v)

S = (u + v) t / 2 [from equations of motion]

putting values and taking S as x since unknown,

x = (5 + 7) 10 / 2

or, x = 12 × 10 / 2

or, x = 6 × 10

or, x = 60

Answer 2 : The distance travelled in this time is 60 metres.

Hope it helps.

by the way, you categorized your question under wrong category (Chemistry). It should be Physics.