Question

A motorcycle moving with a speed of 5m per second is subjected to an acceleration of 0.2 m/sec .calculate the speed of the motorcycle after 10 sec, and the distance traveled in this time

Answer 1

u = 5m/s , a = 0.2m/s^2 , t = 10sec , v = ? , s = ?

From 1st equation of motion ,

v = u + at

where v is final velocity , t is time , a is acceleration , u is initial velocity

=> v = 5 + 0.2(10)

=> v = 5 + 2 = 7m/s

From second equation of motion ,

v^2 - u^2 = 2as

where v is final velocity , u is initial velocity , a is accleration , s is distance

=> 7^2 - 5^2 = 2(0.2)(s)

=> 24 = 0.4 (s) => s = 60m