a motorcycle moving with a speed of 5m/s is subjected to an acceleration of 0.2m/(s)square ,calculate speed after 10 second and distance travelled,. please answer
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Answered by
1
Answer:
speed=7m/s
Step-by-step explanation:
u=5m/s
v=7m/s
a=0.2m/s
t=10s
s=ut+1/2at
put the values
50+10
60m
Answered by
0
Step-by-step explanation:
u =5m/s
a=0.2m/s2
t= 10sec.
s=?
v=?
According to first equation of motion:
v= u+ at
substituting the value
v= 5m/s + 0.2m/s2 ×10 sec
v= 5m/s + 2m/s
v=7m/s.
According to second equation of motion :
s=ut+ Half at square
s= 5m/s × 10 sec +1/2 ×0.2m/s2 × 10 sec × 10 sec
s=50m +1m
s=51m..
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