Math, asked by HAcKerSAM, 1 year ago

a motorcycle moving with a speed of 5m/s is subjected to an acceleration of 0.2m/(s)square ,calculate speed after 10 second and distance travelled,. please answer​

Answers

Answered by somya4160
1

Answer:

speed=7m/s

Step-by-step explanation:

u=5m/s

v=7m/s

a=0.2m/s

t=10s

s=ut+1/2at

put the values

50+10

60m

Answered by shashank9786
0

Step-by-step explanation:

u =5m/s

a=0.2m/s2

t= 10sec.

s=?

v=?

According to first equation of motion:

v= u+ at

substituting the value

v= 5m/s + 0.2m/s2 ×10 sec

v= 5m/s + 2m/s

v=7m/s.

According to second equation of motion :

s=ut+ Half at square

s= 5m/s × 10 sec +1/2 ×0.2m/s2 × 10 sec × 10 sec

s=50m +1m

s=51m..

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