A motorcycle moving with a speed of 5m/s is subjected to an acceleration of 0.2 m/s Sq. Calculate the speed of the motorcycle after 10 second and the distance travelled in this time.
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Speed after 10 sec is 7 m/s and distance travelled is 60m
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Hello,
The initial velocity of the motorcycle = 5m/sec
Acceleration = 0.2 m/sec²
Time =10 seconds
From the equations of the motion we know that
✔️ v = u+at
So,
V = 5 + 0.2 *10 = 5+2 =7 m/sec
So, the final velocity of the object is 7 m/sec
Now,
Again we know that
✔️2as = v²-u²
So, s= v²-u²/2a
So,s= 49 - 25 /0.4 = 24/0.4 =60 m
Therefore, The distance travelled is 60 m
Hope this will be helping you
The initial velocity of the motorcycle = 5m/sec
Acceleration = 0.2 m/sec²
Time =10 seconds
From the equations of the motion we know that
✔️ v = u+at
So,
V = 5 + 0.2 *10 = 5+2 =7 m/sec
So, the final velocity of the object is 7 m/sec
Now,
Again we know that
✔️2as = v²-u²
So, s= v²-u²/2a
So,s= 49 - 25 /0.4 = 24/0.4 =60 m
Therefore, The distance travelled is 60 m
Hope this will be helping you
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