Question

A motorcycle moving with a speed of 5m/s is subjected to an acceleration of 0.2 m/s∧2 Calculate the speed acquired and the distance travelled in this time​

Answer 1

Answer:

Given that

The initial speed of car=u= 5 m/s

Acceleration =a=0.2m/s2

Time=t=10s

We need to calculate the distance

We know that

v = u + at

= 5 + 0.2×10

= 5+2

= 7 m/s

s = ut + 1/2at²

= (5×10) + (1/2)×(2/10)×(10×10)

= 50 + 10

= 60 m

Final speed = 7 m/s

Distance traveled in 10 seconds = 60 m

Answer 2

Answer:

Given:-

• u=5m/s
• v=?
• a=0.2m/s²
• t=10sec

Now, calculating the distance

$\sf \: v=u+at$

$\sf \: v=5+0.2×10$

$\sf \: v=7m/s$

ㅤ

Now distance traveled,

• s=?

$\sf \: v^2=u^2 +2as$

$\sf \implies \: 7^2=5^2 +2×0.2×s$

$\sf \implies 49=25+0.4s$

$\sf \implies 49−25=0.4s$

$\sf \implies s= \cancel \frac{0.4}{24}$

$\sf \implies s=60 \: m$

Distance traveled in 10 seconds = 60 m