Question

a motorcycle moving with a speed of 5m/s
is suleject to an acceleration of 0.2 m/s
calculate the speed of the motor cycle after
10s and the distance travelled in this
time​

Answer 1

1) Given that

The initial speed of car=u= 5 m/s

Acceleration =a=0.2m/s2

Time=t=10s

We need to calculate the distance

We know that

v = u + at

= 5 + 0.2×10

= 5+2

= 7 m/s

s = ut + 1/2at²

= (5×10) + (1/2)×(2/10)×(10×10)

= 50 + 10

= 60 m

Final speed = 7 m/s

Distance traveled in 10 seconds = 60 m

Answer 2

Hope this helps

Given that,

u = 5 m/s

a = 0.2 m/s^2

t = 10s

v = u + at

v = 5 + 0.2 × 10

v = 7 m/s

2as = v^2 - u^2

2 × 0.2 × s = 7^2 - 5^2

0.4 × s = 49 - 25

s = 24/0.4

s = 0.6