A motorcycle moving with a speed of 5m/s obtains an acceleration of 0.2m/s. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled by it in this time
Answers
Answered by
2
v=u+at
v=5+0.2×10
v=5+2
v=7 m/s
Now, th dis. travelled,
s=ut+1/2at^2
s=5×10+1/2×20
s=50+10=60 m
v=5+0.2×10
v=5+2
v=7 m/s
Now, th dis. travelled,
s=ut+1/2at^2
s=5×10+1/2×20
s=50+10=60 m
Answered by
2
v = u + at
= 5 + (0.2 × 10)
= 7 m/s
Speed after 10s is 7 m/s
S = ut + 0.5at^2
= (5 × 10) + (0.5 × 0.2 × 10^2)
= 60 m
Distance travelled in 10s is 60 m
= 5 + (0.2 × 10)
= 7 m/s
Speed after 10s is 7 m/s
S = ut + 0.5at^2
= (5 × 10) + (0.5 × 0.2 × 10^2)
= 60 m
Distance travelled in 10s is 60 m
Similar questions