Question

a motorcycle moving with a speed of 5m/s obtains to an acceleration of 0.2m/s .calculate the speed of the motorcycle after 10sec and the distance travelled by it in this time

Answer 1

u = 5 m/sec
a = 0.2 m/sec ^ 2
t = 10 sec
USING 1ST EQ OF MOTION,
v = u + at
v = 5 + 0.2×10
v = 5 + 2
v = 7 m/sec

FINAL VELOCITY = 7 m/sec

2nd EQ OF MOTION,
s = ut + 1/2 at^2
s = 5 × 10 + 1/2 × 2/10×10×10
s = 50 + 10
s = 60m

DISTANCE = 60 m

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Answer 2

U=5m/s

a=0.2m/s^3

t=10sec

V=u+at

V=5+0.2×10

  =5+2

   =7m/s

S  =ut+ 1/2at^2

   =5×10+1/2×2×10

   =50+10

   =60m

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