A motorcycle moving with a speed of 5m/s subjected to acceleration of 0.2m/s^2 calculate the speed of motorcycle after 10 seconds and the distance travelled in this time
Answers
Answered by
1
Answer:
7m/s
Explanation:
u = 5m/s, a = 0.2m/s.s, t = 10 seconds
On applying v=u+at,
v = 5 + 0.2 x 10
= 5 + 2
= 7 m/s
Answered by
0
Answer:
v = 5.02 m/s
s = 60m
Explanation:
v = u + at
=> v = 5 + (0.2)10
=> v = 5 + (0.2)10
=> v = 5.02 m/s
s = ut + (1/2)a t^2
s = 5(10) + (1/2)(0.2)100
s = 60m
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