A motorcycle moving with a speed of 90km/h is subjected to an acceleration of 0.2 m/s² for 10 sec. Calculate the speed of the motorcycle.
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u=?0m/s
v=90m/s
t=10s
v^2=u^2 +2as
(90)^2 =(0)^2+2×0.2×s
8100=0+0.4s
8100=0.4s
8100÷0.4=s
s=2250
speed =distance/time interval
speed=2250/10
speed=225m/s
v=90m/s
t=10s
v^2=u^2 +2as
(90)^2 =(0)^2+2×0.2×s
8100=0+0.4s
8100=0.4s
8100÷0.4=s
s=2250
speed =distance/time interval
speed=2250/10
speed=225m/s
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