Question

A motorcycle moving with a speed of 90km/h is subjected to an acceleration of 0.2 m/s² for 10 sec. Calculate the speed of the motorcycle.the distance travelled.

Answer 1

Given,

u = 90 km/hr => 2.5 m/s

a = 0.2 $m/s^{2}$

t = 10 s

we can find the speed with motion formulas

v = u + at

v = 2.5 + 0.2(10)

v = 2.5 + 2

v = 4.5 m/s

now distance,

$s = ut +\frac{1}{2} at^{2}$

$s = 2.5(10) +\frac{1}{2} (0.2)(100)$

s =25 + 10

s = 35 m