Question

A motorcycle moving with speed of 18km/h is subjected to an acceleration of 0.2 metre per second square. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled in this time.

Answer 1

✬ Final Velocity = 7 m/s ✬

✬ Distance = 60 m ✬

Explanation:

Given:

• Initial velocity of motorcycle is 18 km/h.
• Acceleration is 0.2 m/s².
• Time is 10 seconds.

To Find:

• Final velocity of motorcycle and Distance travelled

Formula to be used:

• v = u + at (for final velocity)
• s = ut + 1/2at² (for distance)

Solution: Changing the initial velocity into m/s.

➟ u = 18(5/18)

➟ u = 5 m/s

Now put the values on formula

$\implies{\rm }$ v = u + at

$\implies{\rm }$ v = 5 + 0.2(10)

$\implies{\rm }$ v = 5 + 2

$\implies{\rm }$ v = 7

So, Final velocity of bike is 7 m/s.

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ s = 5(10) + 1/2(0.2)(10)²

$\implies{\rm }$ s = 50 + 0.2/2(100)

$\implies{\rm }$ s = 50 + 20/2

$\implies{\rm }$ s = 50 + 10

$\implies{\rm }$ s = 60

Hence, the distance travelled is 60 m.