Question

A motorcycle of mass 180kg running with a speed in 10 s on applying brakes. Calculate the constant retardation of the motorcycle and the retarding force exerted by brakes.​

Answer 1

Answer:

Retardation = 5 m/s²

Retarding force = 900 N

Step-by-step explanation:

★Given:

Mass (m) = 180 kg

Initial velocity (u) = 50 m/s

Final velocity (v) = 0 m/s (As brakes were applied)

Time (t) = 10 s

★Tofind:

Retardation (-a) = ?

Retarding force exerted (-F) =

★Solution:

We are given with initial and final velocities and time, Now we have to find the retardation or -ve acceleration.

We remember,Acceleration(a)=

t

v−u

Here, v = Final velocity

u = Initial velocity

t = time

a = Acceleration

a=10

0−50

a= 10

−50

implies⟹ a = -5 m/s²

∴Retardationis5m/s

2

(or acceleration = -5 m/s²)

By second law of motion we knows,}Force(F)=Mass(m)×Acceleration(a)

Now, we know the acceleration i.e, -5 m/s² and the mass of motorcycle is given so just put all the given values for retarding force.

➳ F = 180 × -5

➳ F = -900 N

∴Retardingforceis900Newton

"Note: Where the word retarding or retardation comes that means something is negative not positive

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Answer 2

Answer:

Retardation = 5 m/s²

Retarding force = 900 N

Explanation:

$\underline{\bigstar\:\textsf{Given:}}$

Mass (m) = 180 kg

Initial velocity (u) = 50 m/s

Final velocity (v) = 0 m/s (As brakes were applied)

Time (t) = 10 s

$\underline{\bigstar\:\textsf{To\:find:}}$

Retardation (-a) = ?

Retarding force exerted (-F) = ?

$\underline{\bigstar\:\textsf{Solution:}}$

We are given with initial and final velocities and time, Now we have to find the retardation or -ve acceleration.

We remember, $\blue{\sf{Acceleration(a)\:=\:\dfrac{v\:-\:u}{t}}}$

Here, v = Final velocity

$\:$ u = Initial velocity

$\:$ t = time

$\:$ a = Acceleration

$\implies\:\sf{a\:=\:\dfrac{0\:-\:50}{10}}$

$\implies\:\sf{a\:=\:\dfrac{-50}{10}}$

$\implies$ a = -5 m/s²

$\underline{\underline{\sf{\therefore\:Retardation\:is\:5\:m/s^2}}}$

(or acceleration = -5 m/s²)

By second law of motion we knows, $\orange{\sf{Force(F)\:=\:Mass(m)\:\times\:Acceleration(a)}}$

Now, we know the acceleration i.e, -5 m/s² and the mass of motorcycle is given so just put all the given values for retarding force.

➳ F = 180 × -5

➳ F = -900 N

➳ $\underline{\underline{\sf{\therefore\:Retarding\:force\:is\:900\:Newton}}}$

"Note: Where the word retarding or retardation comes that means something is negative not positive."