Question

A motorcycle of mass 2000kg is moving over a horizontal road, with uniform velocity. If this
motorcycle has to be stopped with a negative acceleration of -1.5m/s 2 , then what is the force
of friction between the tyres of motorcycle and the road?

Answer 1

Answer:

plz mark as Brainlist

Explanation:

Velocity of car is u=72km/hr=20m/s

Now loss in KE will be equal to work done against friction

So μmgs=

2

mv

2

⇒s=200/4=50m