A motorcycle of mass 2000kg is moving over a horizontal road, with uniform velocity. If this
motorcycle has to be stopped with a negative acceleration of -1.5m/s 2 , then what is the force
of friction between the tyres of motorcycle and the road?
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Answer:
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Explanation:
Velocity of car is u=72km/hr=20m/s
Now loss in KE will be equal to work done against friction
So μmgs=
2
mv
2
⇒s=200/4=50m
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