Question

a motorcycle originally cost Rs. 40000. Its has decreased by 22% what is cost now

Answer 1

Reduced cost = (Total price × reduced%)/100
= (40000×22)/100
= 8800

Its cost is
40000- 8800
= 31200

Hope it helps. Mark it brainliest.

Answer 2

Answer:

$\red { New \: cost \:price\:of \: motorcycle }$

$\green {= Rs\: 31200 }$

Step-by-step explanation:

$Original\: cost \: of \: a \: motorcycle(c.p) \\= Rs\:40000$

$Decreased (d) = 22\%$

$New \: cost \:price = c.p \left( \frac{100-d}{100}\right)\\= 40000\left(\frac{100-22}{100}\right)\\=40000\times \frac{78}{100}\\= 400 \times 78\\= Rs\:31200$

Therefore.,

$\red { New \: cost \:price\:of \: motorcycle }$

$\green {= Rs\: 31200 }$

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