Question

A motorcycle running at 5m/s picks up a velocity of 30m/s in 5s. Calculate acceleration and distance covered during acceleration

Answer 1

Hey! ! !

Solution :-

☆ Given :-

● U = 5m/s ... ( Initial velocity )

● V = 30m/s ..... ( Final Velocity )

● t = 5 sec

:- a = v - u / t

=> 30 - 5 /5

= 25/5

:- a = 5 m/s^2

From the second equation of motion : -

☆ S = ut + 1/2at^2

=> S = 5×5 + 1/2 × 5×5×5

:- S = 87.5 m

☆ ☆ ☆ Hop its helpful ☆ ☆ ☆

☆ Regards :- ♡♡《 Nitish kr singh 》♡♡

Answer 2

$\large\blue{heya mate!!}$

U= 5m/s

V=10m/s

S=50m

We know,

2as=v^2-u^2

A=(10×10)-(5×5)/2×50

A=75/100

A=0.75m/s2

We know

A=v-u/t

75/100×t=10-5

T=3.75 seconds