A motorcycle starting from rest covers 200 metre distance in 6 second. Calculate final velocity and acceleration of the motorcycle
Answers
Question:-
A motorcycle starting from rest covers 200 metre distance in 6 second. Calculate final velocity and acceleration of the motorcycle.
Answer:-
- The acceleration of motorcycle is 5.56 m/s².
- The final velocity is 33.34 m/s.
To find:-
- final velocity
- acceleration of motorcycle
Solution:-
- Displacement = 200 m
- Time taken = 6 seconds
- The final velocity is 33.34 m/s.
___________________________
ACCELERATION:-
- initial velocity (u) = 0 m/s
- Final velocity (v) = 33.34 m/s
- Time taken (t) = 6 seconds
- The acceleration of motorcycle is 5.56 m/s².
Question:-
A motorcycle starting from rest covers 200 metre distance in 6 second. Calculate final velocity and acceleration of the motorcycle.
Answer:-
The acceleration of motorcycle is 5.56 m/s².
The final velocity is 33.34 m/s.
To find:-
final velocity
acceleration of motorcycle
Solution:-
\boxed{ \large{velocity = \frac{displacement}{time} }}
velocity=
time
displacement
Displacement = 200 m
Time taken = 6 seconds
\begin{gathered}\implies \: velocity \: = \frac{200}{6} \\ \\ \implies \: velocity \: = 33.34 \: m {s}^{ - 1}\end{gathered}
⟹velocity=
6
200
⟹velocity=33.34ms
−1
The final velocity is 33.34 m/s.
___________________________
ACCELERATION:-
initial velocity (u) = 0 m/s
Final velocity (v) = 33.34 m/s
Time taken (t) = 6 seconds
\boxed{ \large{acceleration = \frac{v - u}{t} }}
acceleration=
t
v−u
\begin{gathered}\implies \: acceleration = \frac{33.34 - 0}{6} \\ \\ \implies \: acceleration = \frac{33.34}{6} \\ \\ \implies \: acceleration = 5.56 \: {ms}^{ - 2}\end{gathered}
⟹acceleration=
6
33.34−0
⟹acceleration=
6
33.34
⟹acceleration=5.56ms
−2
The acceleration of motorcycle is 5.56 m/s².