Science, asked by mrbinaykumarprajapat, 6 months ago

A motorcycle starting from rest covers 200 metre distance in 6 second. Calculate final velocity and acceleration of the motorcycle​

Answers

Answered by Anonymous
44

Question:-

A motorcycle starting from rest covers 200 metre distance in 6 second. Calculate final velocity and acceleration of the motorcycle.

Answer:-

  • The acceleration of motorcycle is 5.56 m/s².
  • The final velocity is 33.34 m/s.

To find:-

  • final velocity
  • acceleration of motorcycle

Solution:-

 \boxed{ \large{velocity =  \frac{displacement}{time} }}

  • Displacement = 200 m
  • Time taken = 6 seconds

 \implies \: velocity \:  =  \frac{200}{6}  \\  \\  \implies \: velocity \:  = 33.34 \: m {s}^{ - 1}

  • The final velocity is 33.34 m/s.

___________________________

ACCELERATION:-

  • initial velocity (u) = 0 m/s
  • Final velocity (v) = 33.34 m/s
  • Time taken (t) = 6 seconds

 \boxed{ \large{acceleration =  \frac{v - u}{t} }}

 \implies \: acceleration =  \frac{33.34 - 0}{6}  \\  \\ \implies \: acceleration =  \frac{33.34}{6}  \\  \\ \implies \: acceleration = 5.56 \:  {ms}^{ - 2}

  • The acceleration of motorcycle is 5.56 m/s².
Answered by negigungun123
3

Question:-

A motorcycle starting from rest covers 200 metre distance in 6 second. Calculate final velocity and acceleration of the motorcycle.

Answer:-

The acceleration of motorcycle is 5.56 m/s².

The final velocity is 33.34 m/s.

To find:-

final velocity

acceleration of motorcycle

Solution:-

\boxed{ \large{velocity = \frac{displacement}{time} }}

velocity=

time

displacement

Displacement = 200 m

Time taken = 6 seconds

\begin{gathered}\implies \: velocity \: = \frac{200}{6} \\ \\ \implies \: velocity \: = 33.34 \: m {s}^{ - 1}\end{gathered}

⟹velocity=

6

200

⟹velocity=33.34ms

−1

The final velocity is 33.34 m/s.

___________________________

ACCELERATION:-

initial velocity (u) = 0 m/s

Final velocity (v) = 33.34 m/s

Time taken (t) = 6 seconds

\boxed{ \large{acceleration = \frac{v - u}{t} }}

acceleration=

t

v−u

\begin{gathered}\implies \: acceleration = \frac{33.34 - 0}{6} \\ \\ \implies \: acceleration = \frac{33.34}{6} \\ \\ \implies \: acceleration = 5.56 \: {ms}^{ - 2}\end{gathered}

⟹acceleration=

6

33.34−0

⟹acceleration=

6

33.34

⟹acceleration=5.56ms

−2

The acceleration of motorcycle is 5.56 m/s².

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