Question

A motorcycle, starting from rest moves with constant acceleration of +2.6 m/s. After travelling a distance of 120m, it accelerates with -1.5m/s² till its velocity becomes +12m/s. Calculate the total distance travelled by the motorcycle during this journey.

Answer 1

Answer:

280 m

Explanation:

Initial velocity of motor cycle = 0 m/s

acceleration = 2.6 m/s²

V² - U² = 2aS

=> V² - 0 = 2 * 2.6 * 120

=> V² = 624

accelerates with -1.5m/s² till its velocity becomes +12m/s

12² - 624 = 2(-1.5)S

=> 144 - 624 = -3S

=> S = 480/3

=> S = 160

total distance travelled by the motorcycle during this journey = 120 + 160

= 280 m

Answer 2

Answer:

Total distance traveled y motor cycle will be 120+160= 280m

Explanation:

Initial velocity of motor cycle = u= 0 m/s

acceleration =a= 2.6 m/s²

s=120m/s

From third equation of motion :

v²- u²=2as

v²-0²=2 x 2.6 x 120

v²=624

The motor cycle accelerates with -1.5m/s² till its velocity becomes 12m/s

v²-u²=2as

12²-624=2x-1.5x s

144- 624=-3s

-480=-3s

s=480/3

s=160m

so total distance traveled by motor cycle will be 120+160= 280m