Question

A motorcycle starts from rest and maintains a constant acceleration of 3m/s^2 for 6s and then a costant acceleration of 2m/s^2 for another 6s.what is the aquired velocity and total distance travelled

Answer 1

I. v= u+at            II.v=u+at    (from I)
   v= 0+3x6            v=18+2x6
   v=18                   v=30
   ∴v= 30 m/s     


I.s=ut+1/2at^2                            II.s=ut+1/2at^2
  s=0x6+1/2x3x6x6                       s=30x6+1/2x2x6x6
  s=0+1.5x6x6                               s=180+6x6 
  s=54m                                         s=180+36
                                                      s=216m
total distance=260 m