A motorcycle starts from rest and reaches a speed of 6m/s after travelling uniform acceleration for 3s. what is his acceleration ?
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By using equation of motion
a=(v-u)/t
a=(6-0)/3
a=2m/s²
a=(v-u)/t
a=(6-0)/3
a=2m/s²
Answered by
2
2 m/s2 is the right answer.....
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