Question

A motorcycle starts to move from rest with a constant acceleration of 1.5 m per second square for 2 minutes the distance travelled by the motorcycle in this time will be

Answer 1

hey frnd ur answer :

u = 0

a = 1.5 m/s²

t = 2 mins = 2*60 sec = 120 sec

S = ut + 1/2at²

S = 0*120 + 1/2*1.5*(120)²

S = 0 + 1.5/2*14400

S = 1.5*7200

S = 10800 m

S = 10.8 km

Answer 2

The distance travelled by the motorcycle in this time is 10800 meters

Explanation:

Given that,

Initial speed of a motorcycle, u = 0

Acceleration of the motorcycle, $a=1.5\ m/s^2$

Time, t = 2 min = 120 s

We need to find the distance travelled by the motorcycle in this time. It can be calculated using second equation of motion. It is given by :

$d=ut+\dfrac{1}{2}at^2$

Here, u = 0

$d=\dfrac{1}{2}at^2$

$d=\dfrac{1}{2}\times 1.5\times (120)^2$

d = 10800 m

So, the distance travelled by the motorcycle in this time is 10800 meters. Hence, this is the required solution.

Learn more,

Equation of motion

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