A motorcycle travelling a t 26 /ℎ is stopped by applying brakes. It accelerates uniformly in
the opposite direction. It stops in 5 . Plot speed-time graph and calculate the distance travelled by
the motorcycle after the brakes were applied.
Answers
Answered by
0
Answer:
(A) : Initial speed of the car A u=52 kmh
−1
=52×
18
5
=14.44 ms
−1
The car stops in 5 seconds i.e v=0 at t=5
(A) : Initial speed of the car A u=3 kmh
−1
=3×
18
5
=0.83 ms
−1
The car stops in 10 seconds i.e v=0 at t=10
With the help of these initial and final points for both the cases, we can plot the graph of speed vs time.
Area under the speed-time graph gives the distance covered.
∴ Distance covered by car A x
A
=
2
1
×14.44×5=36.1 m
∴ Distance covered by car A x
B
=
2
1
×0.83×10=4.15 m
Thus car A travels more distance than B.
Answered by
0
Answer:1.2.89 ms²
Explanation: 26km/hr= 1.44m/s
acceleration = (1.44/5)m/s²
=O. 29
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