Question

A motorcycle was 32m/s. It took the motorcycle a distance 75 m to stop. How long did it take the motorcycle to stop?

Answer 1

Explanation:

Deceleration value of motorcycle = 6.83 m/s^26.83m/s

2

Explanation:

We have equation of motion, v^2=u^2+2asv

2

=u

2

+2as , where u is the initial velocity, v is the final velocity, s is the displacement and a is the acceleration.

In this case we have final velocity = 0 m/s, initial velocity = 32 m/s, and displacement = 75 m, now we need to find deceleration value.

Substituting

\begin{gathered}0^2 = 32^2+2*a*75\\ \\ a = -6.83 m/s^2\end{gathered}

0

2

=32

2

+2∗a∗75

a=−6.83m/s

2

So, Acceleration value of motorcycle = -6.83 m/s^2−6.83m/s

2

Deceleration value of motorcycle = 6.83 m/s^26.83m/s

2