Question

A motorcycle was initially moving with a velocity of 80 m/s, suddenly after seeing a child in front of him, the motorcycle rider applied a brake and motorcycle comes in rest after 16 seconds. Calculate (a) acceleration of the motorcycle (b) distance covered.​

Answer 1

Answer:

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Answer 2

Explanation:

Speed=20m/s,d=50m,retardation=5m/s2

Let the ppossible reaction time be ts So the car moves 20tm And applied breaks with retardation 5m/s2

So, the total distance under retardation is ≤50m

Thus the distance under  the application of retardation =2×5202−02=s′⇒s′=40m

Therefore,  20ts+40≤=50⇒20ts≤50−40⇒20ts=10⇒ts≤21≤0.5s