A motorcycle was initially moving with a velocity of 80 m/s, suddenly after seeing a child in front of him, the motorcycle rider applied a brake and motorcycle comes in rest after 16 seconds. Calculate (a) acceleration of the motorcycle (b) distance covered.
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Answered by
7
Answer:
(a) -5 m/s²
(b) 640 m
Explanation:
Given :
A motorcycle was initially moving with a velocity of 80 m/s, suddenly after seeing a child in front of him, the motorcycle rider applied a brake and motorcycle comes in rest after 16 seconds.
To find :
(a) acceleration of the motorcycle
(b) distance covered
Solution :
Initial velocity, u = 80 m/s
final velocity, v = 0 m/s
time taken, t = 16 seconds
Using v = u + at :
0 = 80 + a(16)
16a = -80
a = -80/16
a = -5 m/s²
Therefore, the acceleration of the motorcycle is -5 m/s²
Now applying v² - u² = 2as :
0² - 80² = 2(-5)(s)
-6400 = -10s
10s = 6400
s = 6400/10
s = 640 m
∴ The distance covered is 640 m.
Answered by
3
- initial velocity=u=80m/s
- Final velocity=v=0m/s
- Time=t=16s
- Acceleration=a=?
- Distance=s=?
We know
Now using 2nd equation of kinematics
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