a motorcycle weighs 4500 N. if the pressure of the tyres on the road is 1000000 Pa , what is the area of each tyre in contact with the road. (remember the vehicle has two tyre )
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Hi!
4500N divided on two tyres is 2250N tyres each.
No, let's first take the whole thing ya?
Now, P = F/A
100000 = 4500/A
A = F/P
A = 4500/ 1000000
= 45/10000
= 4.5 x 10-³ (it is actually power of minus three)
4.5 x 10-³m² total area in contact
or 0.0045m²
each tyre = 0.0045/2
= 0.00225m² surface area of each tyre is in contact with the street.
Hope you found my answer useful .
4500N divided on two tyres is 2250N tyres each.
No, let's first take the whole thing ya?
Now, P = F/A
100000 = 4500/A
A = F/P
A = 4500/ 1000000
= 45/10000
= 4.5 x 10-³ (it is actually power of minus three)
4.5 x 10-³m² total area in contact
or 0.0045m²
each tyre = 0.0045/2
= 0.00225m² surface area of each tyre is in contact with the street.
Hope you found my answer useful .
sree3188:
thank you
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