Question

A motorcyclist accelerates his bike at a uniform rate of 1.5 m.s-2 for 6 seconds and then travels with a uniform velocity. If his initial velocity was 11 m.s-1, determine his final velocity.

Answer 1

To find :

• we need to determine the final velocity of motorcyclist

Solution : --

• Acceleration (a) = 1.5m/s²
• Time (t) = 6 seconds
• Initial velocity (u) = 11m/s

By using first equation of motion : --

• v = u + at

• Substituting values : --

›› v = u + at

›› v = 11 + 1.5 × 6

›› v = 11 + 9

›› v = 20m/s

Hence,

• Final velocity of motorcyclist is 20m/s .

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• Equations of Motion : --

First equation of motion :-

★ v = u + at

Second equation of motion : -

★ S = ut + 1/2* at²

Third Equation of Motion : -

★ v² = u² + 2as

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Answer 2

Answer:

20 m/s

Explanation:

Given; acceleration is 1.5 m/s², time is 6 sec and initial velocity is 11 m/s.

To find: Final velocity

Using the first equation of motion,

v = u + at

Substitute the values,

→ v = 11 + 1.5(6)

→ v = 11 + 9.0

→ v = 11 + 9

→ v = 20

Hence, the final velocity of the motorcyclist is 20 m/s.

Additional Information

First equation of motion

• v = u + at

Second equation of motion,

• s = ut + 1/2 at²

Third equation of motion,

• v² - u² = 2as