A motorcyclist along with his motorcycle has a mass of 250kg while driving at 36km/h , he
accelerates for 10s and picks up a velocity of 108 km/h Calcuate a) initial momentum b) final
momentum c) the extra force developed by the engine
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Answer:
initial velocity, u = 72 km/h = 72× 5/18 = 20 m/s
Final below, v = 0
Distance for stopping, s = 8m
We know that v^2 - u^2 = 2as
0 - 20^2 = 2×a×8
16a = -400
a = -400/16 = -25 m/s^2
So retardation of the motorcycle = 25 m/s^2
Mass = 160 kg
Force = ma = 160×25 = 4000 N
Retarding force is 4000 N
Explanation:
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